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198 lines
5.5 KiB
C
198 lines
5.5 KiB
C
/*
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* pi.c
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*
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* Compute pi to an arbitrary number of digits. Uses Machin's formula,
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* like everyone else on the planet:
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*
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* pi = 16 * arctan(1/5) - 4 * arctan(1/239)
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*
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* This is pretty effective for up to a few thousand digits, but it
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* gets pretty slow after that.
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*
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* ***** BEGIN LICENSE BLOCK *****
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* Version: MPL 1.1/GPL 2.0/LGPL 2.1
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*
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* The contents of this file are subject to the Mozilla Public License Version
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* 1.1 (the "License"); you may not use this file except in compliance with
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* the License. You may obtain a copy of the License at
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* http://www.mozilla.org/MPL/
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*
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* Software distributed under the License is distributed on an "AS IS" basis,
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* WITHOUT WARRANTY OF ANY KIND, either express or implied. See the License
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* for the specific language governing rights and limitations under the
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* License.
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*
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* The Original Code is the MPI Arbitrary Precision Integer Arithmetic library.
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*
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* The Initial Developer of the Original Code is
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* Michael J. Fromberger.
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* Portions created by the Initial Developer are Copyright (C) 1999
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* the Initial Developer. All Rights Reserved.
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*
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* Contributor(s):
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*
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* Alternatively, the contents of this file may be used under the terms of
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* either the GNU General Public License Version 2 or later (the "GPL"), or
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* the GNU Lesser General Public License Version 2.1 or later (the "LGPL"),
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* in which case the provisions of the GPL or the LGPL are applicable instead
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* of those above. If you wish to allow use of your version of this file only
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* under the terms of either the GPL or the LGPL, and not to allow others to
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* use your version of this file under the terms of the MPL, indicate your
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* decision by deleting the provisions above and replace them with the notice
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* and other provisions required by the GPL or the LGPL. If you do not delete
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* the provisions above, a recipient may use your version of this file under
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* the terms of any one of the MPL, the GPL or the LGPL.
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*
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* ***** END LICENSE BLOCK ***** */
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/* $Id: pi.c,v 1.3 2004/04/27 23:04:37 gerv%gerv.net Exp $ */
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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#include <limits.h>
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#include <time.h>
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#include "mpi.h"
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mp_err arctan(mp_digit mul, mp_digit x, mp_digit prec, mp_int *sum);
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int main(int argc, char *argv[])
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{
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mp_err res;
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mp_digit ndigits;
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mp_int sum1, sum2;
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clock_t start, stop;
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int out = 0;
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/* Make the user specify precision on the command line */
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if(argc < 2) {
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fprintf(stderr, "Usage: %s <num-digits>\n", argv[0]);
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return 1;
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}
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if((ndigits = abs(atoi(argv[1]))) == 0) {
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fprintf(stderr, "%s: you must request at least 1 digit\n", argv[0]);
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return 1;
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}
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start = clock();
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mp_init(&sum1); mp_init(&sum2);
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/* sum1 = 16 * arctan(1/5) */
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if((res = arctan(16, 5, ndigits, &sum1)) != MP_OKAY) {
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fprintf(stderr, "%s: arctan: %s\n", argv[0], mp_strerror(res));
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out = 1; goto CLEANUP;
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}
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/* sum2 = 4 * arctan(1/239) */
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if((res = arctan(4, 239, ndigits, &sum2)) != MP_OKAY) {
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fprintf(stderr, "%s: arctan: %s\n", argv[0], mp_strerror(res));
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out = 1; goto CLEANUP;
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}
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/* pi = sum1 - sum2 */
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if((res = mp_sub(&sum1, &sum2, &sum1)) != MP_OKAY) {
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fprintf(stderr, "%s: mp_sub: %s\n", argv[0], mp_strerror(res));
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out = 1; goto CLEANUP;
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}
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stop = clock();
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/* Write the output in decimal */
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{
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char *buf = malloc(mp_radix_size(&sum1, 10));
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if(buf == NULL) {
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fprintf(stderr, "%s: out of memory\n", argv[0]);
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out = 1; goto CLEANUP;
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}
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mp_todecimal(&sum1, buf);
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printf("%s\n", buf);
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free(buf);
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}
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fprintf(stderr, "Computation took %.2f sec.\n",
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(double)(stop - start) / CLOCKS_PER_SEC);
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CLEANUP:
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mp_clear(&sum1);
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mp_clear(&sum2);
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return out;
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}
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/* Compute sum := mul * arctan(1/x), to 'prec' digits of precision */
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mp_err arctan(mp_digit mul, mp_digit x, mp_digit prec, mp_int *sum)
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{
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mp_int t, v;
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mp_digit q = 1, rd;
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mp_err res;
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int sign = 1;
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prec += 3; /* push inaccuracies off the end */
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mp_init(&t); mp_set(&t, 10);
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mp_init(&v);
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if((res = mp_expt_d(&t, prec, &t)) != MP_OKAY || /* get 10^prec */
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(res = mp_mul_d(&t, mul, &t)) != MP_OKAY || /* ... times mul */
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(res = mp_mul_d(&t, x, &t)) != MP_OKAY) /* ... times x */
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goto CLEANUP;
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/*
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The extra multiplication by x in the above takes care of what
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would otherwise have to be a special case for 1 / x^1 during the
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first loop iteration. A little sneaky, but effective.
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We compute arctan(1/x) by the formula:
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1 1 1 1
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- - ----- + ----- - ----- + ...
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x 3 x^3 5 x^5 7 x^7
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We multiply through by 'mul' beforehand, which gives us a couple
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more iterations and more precision
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*/
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x *= x; /* works as long as x < sqrt(RADIX), which it is here */
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mp_zero(sum);
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do {
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if((res = mp_div_d(&t, x, &t, &rd)) != MP_OKAY)
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goto CLEANUP;
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if(sign < 0 && rd != 0)
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mp_add_d(&t, 1, &t);
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if((res = mp_div_d(&t, q, &v, &rd)) != MP_OKAY)
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goto CLEANUP;
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if(sign < 0 && rd != 0)
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mp_add_d(&v, 1, &v);
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if(sign > 0)
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res = mp_add(sum, &v, sum);
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else
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res = mp_sub(sum, &v, sum);
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if(res != MP_OKAY)
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goto CLEANUP;
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sign *= -1;
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q += 2;
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} while(mp_cmp_z(&t) != 0);
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/* Chop off inaccurate low-order digits */
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mp_div_d(sum, 1000, sum, NULL);
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CLEANUP:
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mp_clear(&v);
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mp_clear(&t);
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return res;
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}
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/*------------------------------------------------------------------------*/
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/* HERE THERE BE DRAGONS */
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