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[fix] compute the order of results only once per search
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485da54961
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5b5478bbd9
@ -380,7 +380,9 @@ def index():
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plugins.call('post_search', request, locals())
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for result in search.result_container.get_ordered_results():
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results = search.result_container.get_ordered_results()
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for result in results:
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plugins.call('on_result', request, locals())
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if not search.paging and engines[result['engine']].paging:
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@ -425,13 +427,13 @@ def index():
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if search.request_data.get('format') == 'json':
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return Response(json.dumps({'query': search.query,
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'number_of_results': number_of_results,
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'results': search.result_container.get_ordered_results()}),
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'results': results}),
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mimetype='application/json')
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elif search.request_data.get('format') == 'csv':
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csv = UnicodeWriter(cStringIO.StringIO())
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keys = ('title', 'url', 'content', 'host', 'engine', 'score')
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csv.writerow(keys)
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for row in search.result_container.get_ordered_results():
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for row in results:
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row['host'] = row['parsed_url'].netloc
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csv.writerow([row.get(key, '') for key in keys])
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csv.stream.seek(0)
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@ -442,7 +444,7 @@ def index():
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elif search.request_data.get('format') == 'rss':
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response_rss = render(
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'opensearch_response_rss.xml',
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results=search.result_container.get_ordered_results(),
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results=results,
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q=search.request_data['q'],
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number_of_results=number_of_results,
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base_url=get_base_url()
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@ -451,7 +453,7 @@ def index():
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return render(
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'results.html',
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results=search.result_container.get_ordered_results(),
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results=results,
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q=search.request_data['q'],
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selected_categories=search.categories,
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paging=search.paging,
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